-(x^2+x+10)+8=1

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Solution for -(x^2+x+10)+8=1 equation: 



-(x^2+x+10)+8=1

We move all terms to the left:

-(x^2+x+10)+8-(1)=0

We add all the numbers together, and all the variables

-(x^2+x+10)+7=0

We get rid of parentheses

-x^2-x-10+7=0

We add all the numbers together, and all the variables

-1x^2-1x-3=0

a = -1; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·(-1)·(-3)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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